If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1314=x^2
We move all terms to the left:
1314-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+1314=0
a = -1; b = 0; c = +1314;
Δ = b2-4ac
Δ = 02-4·(-1)·1314
Δ = 5256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5256}=\sqrt{36*146}=\sqrt{36}*\sqrt{146}=6\sqrt{146}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{146}}{2*-1}=\frac{0-6\sqrt{146}}{-2} =-\frac{6\sqrt{146}}{-2} =-\frac{3\sqrt{146}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{146}}{2*-1}=\frac{0+6\sqrt{146}}{-2} =\frac{6\sqrt{146}}{-2} =\frac{3\sqrt{146}}{-1} $
| 2y-5=2y+19 | | 2z-5=2z+19 | | -3z-8=115 | | 2*(4+x)=18+5x+20 | | X^4-2x^2-16=0 | | x^2-8x-43=-21 | | S=(16-2)x180 | | 2(t-1=4 | | 4+2x+6=10 | | 25+q=44 | | 48+q=290 | | 17+q=58 | | 25+q=51 | | 120+m=210 | | r+9=3 | | X2-7x+38=0 | | 15t=57 | | x=37*8+15 | | 3x-2=2x+7= | | b/2+-3.5=-1.64 | | 3w-7=-4 | | 2u+-4=-2 | | q/2+4.51=7.51 | | y/4+5.7=9.1 | | 8x+1-9x-4=180 | | 8x+1+9x-4=180 | | 5(3c+)=50 | | 2x-29-10x+5=180 | | 4x-3-3x+22=180 | | x-30+3x-10=180 | | 9x-9+x-1=180 | | -2-10u=-8u+8 |